Average Error: 0.3 → 0.3
Time: 3.7s
Precision: 64
\[\left(\left(x \cdot 3\right) \cdot y\right) \cdot y\]
↓
\[\left(\left(x \cdot 3\right) \cdot y\right) \cdot y\]
\left(\left(x \cdot 3\right) \cdot y\right) \cdot y
↓
\left(\left(x \cdot 3\right) \cdot y\right) \cdot y
double f(double x, double y) {
        double r768794 = x;
        double r768795 = 3.0;
        double r768796 = r768794 * r768795;
        double r768797 = y;
        double r768798 = r768796 * r768797;
        double r768799 = r768798 * r768797;
        return r768799;
}
↓
double f(double x, double y) {
        double r768800 = x;
        double r768801 = 3.0;
        double r768802 = r768800 * r768801;
        double r768803 = y;
        double r768804 = r768802 * r768803;
        double r768805 = r768804 * r768803;
        return r768805;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.3
Target0.2
Herbie0.3
\[\left(x \cdot \left(3 \cdot y\right)\right) \cdot y\]

Derivation

  1. Initial program 0.3

    \[\left(\left(x \cdot 3\right) \cdot y\right) \cdot y\]

  2. Final simplification0.3

    \[\leadsto \left(\left(x \cdot 3\right) \cdot y\right) \cdot y\]

Reproduce

herbie shell --seed 2020036 +o rules:numerics
(FPCore (x y)
  :name "Diagrams.Segment:$catParam from diagrams-lib-1.3.0.3, B"
  :precision binary64

  :herbie-target
  (* (* x (* 3 y)) y)

  (* (* (* x 3) y) y))