Average Error: 0.0 → 0.0
Time: 756.0ms
Precision: 64
\[0.0 \le x \le 2\]
\[x + x \cdot x\]
\[x + x \cdot x\]
x + x \cdot x
x + x \cdot x
double f(double x) {
        double r84095 = x;
        double r84096 = r84095 * r84095;
        double r84097 = r84095 + r84096;
        return r84097;
}

double f(double x) {
        double r84098 = x;
        double r84099 = r84098 * r84098;
        double r84100 = r84098 + r84099;
        return r84100;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.0
Target0.0
Herbie0.0
\[\left(1 + x\right) \cdot x\]

Derivation

  1. Initial program 0.0

    \[x + x \cdot x\]
  2. Final simplification0.0

    \[\leadsto x + x \cdot x\]

Reproduce

herbie shell --seed 2020036 
(FPCore (x)
  :name "Expression 2, p15"
  :precision binary64
  :pre (<= 0.0 x 2)

  :herbie-target
  (* (+ 1 x) x)

  (+ x (* x x)))