Average Error: 0.1 → 0.1
Time: 3.0s
Precision: 64
\[x \cdot \left(y + z\right) + z \cdot 5\]
\[x \cdot \left(y + z\right) + z \cdot 5\]
x \cdot \left(y + z\right) + z \cdot 5
x \cdot \left(y + z\right) + z \cdot 5
double f(double x, double y, double z) {
        double r604178 = x;
        double r604179 = y;
        double r604180 = z;
        double r604181 = r604179 + r604180;
        double r604182 = r604178 * r604181;
        double r604183 = 5.0;
        double r604184 = r604180 * r604183;
        double r604185 = r604182 + r604184;
        return r604185;
}

double f(double x, double y, double z) {
        double r604186 = x;
        double r604187 = y;
        double r604188 = z;
        double r604189 = r604187 + r604188;
        double r604190 = r604186 * r604189;
        double r604191 = 5.0;
        double r604192 = r604188 * r604191;
        double r604193 = r604190 + r604192;
        return r604193;
}

Error

Bits error versus x

Bits error versus y

Bits error versus z

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.1
Target0.1
Herbie0.1
\[\left(x + 5\right) \cdot z + x \cdot y\]

Derivation

  1. Initial program 0.1

    \[x \cdot \left(y + z\right) + z \cdot 5\]
  2. Final simplification0.1

    \[\leadsto x \cdot \left(y + z\right) + z \cdot 5\]

Reproduce

herbie shell --seed 2020036 
(FPCore (x y z)
  :name "Graphics.Rendering.Plot.Render.Plot.Legend:renderLegendOutside from plot-0.2.3.4, C"
  :precision binary64

  :herbie-target
  (+ (* (+ x 5) z) (* x y))

  (+ (* x (+ y z)) (* z 5)))