Average Error: 34.2 → 8.6
Time: 8.6s
Precision: 64
\[\frac{\left(-b_2\right) + \sqrt{b_2 \cdot b_2 - a \cdot c}}{a}\]
\[\begin{array}{l} \mathbf{if}\;b_2 \le -2.14194017547317126 \cdot 10^{130}:\\ \;\;\;\;\frac{1}{2} \cdot \frac{c}{b_2} - 2 \cdot \frac{b_2}{a}\\ \mathbf{elif}\;b_2 \le -1.5120874391809866 \cdot 10^{-204}:\\ \;\;\;\;\left(\left(-b_2\right) + \sqrt{b_2 \cdot b_2 - a \cdot c}\right) \cdot \frac{1}{a}\\ \mathbf{elif}\;b_2 \le 0.0231735748307204843:\\ \;\;\;\;\frac{\frac{1}{\frac{\frac{\left(-b_2\right) - \sqrt{b_2 \cdot b_2 - a \cdot c}}{a}}{c}}}{a}\\ \mathbf{elif}\;b_2 \le 4.6383712677255495 \cdot 10^{30}:\\ \;\;\;\;\frac{-1}{2} \cdot \frac{c}{b_2}\\ \mathbf{elif}\;b_2 \le 2.29266152734135 \cdot 10^{122}:\\ \;\;\;\;\frac{\frac{0 + a \cdot c}{\left(-b_2\right) - \sqrt{b_2 \cdot b_2 - a \cdot c}}}{a}\\ \mathbf{else}:\\ \;\;\;\;\frac{-1}{2} \cdot \frac{c}{b_2}\\ \end{array}\]
\frac{\left(-b_2\right) + \sqrt{b_2 \cdot b_2 - a \cdot c}}{a}
\begin{array}{l}
\mathbf{if}\;b_2 \le -2.14194017547317126 \cdot 10^{130}:\\
\;\;\;\;\frac{1}{2} \cdot \frac{c}{b_2} - 2 \cdot \frac{b_2}{a}\\

\mathbf{elif}\;b_2 \le -1.5120874391809866 \cdot 10^{-204}:\\
\;\;\;\;\left(\left(-b_2\right) + \sqrt{b_2 \cdot b_2 - a \cdot c}\right) \cdot \frac{1}{a}\\

\mathbf{elif}\;b_2 \le 0.0231735748307204843:\\
\;\;\;\;\frac{\frac{1}{\frac{\frac{\left(-b_2\right) - \sqrt{b_2 \cdot b_2 - a \cdot c}}{a}}{c}}}{a}\\

\mathbf{elif}\;b_2 \le 4.6383712677255495 \cdot 10^{30}:\\
\;\;\;\;\frac{-1}{2} \cdot \frac{c}{b_2}\\

\mathbf{elif}\;b_2 \le 2.29266152734135 \cdot 10^{122}:\\
\;\;\;\;\frac{\frac{0 + a \cdot c}{\left(-b_2\right) - \sqrt{b_2 \cdot b_2 - a \cdot c}}}{a}\\

\mathbf{else}:\\
\;\;\;\;\frac{-1}{2} \cdot \frac{c}{b_2}\\

\end{array}
double f(double a, double b_2, double c) {
        double r28167 = b_2;
        double r28168 = -r28167;
        double r28169 = r28167 * r28167;
        double r28170 = a;
        double r28171 = c;
        double r28172 = r28170 * r28171;
        double r28173 = r28169 - r28172;
        double r28174 = sqrt(r28173);
        double r28175 = r28168 + r28174;
        double r28176 = r28175 / r28170;
        return r28176;
}

double f(double a, double b_2, double c) {
        double r28177 = b_2;
        double r28178 = -2.1419401754731713e+130;
        bool r28179 = r28177 <= r28178;
        double r28180 = 0.5;
        double r28181 = c;
        double r28182 = r28181 / r28177;
        double r28183 = r28180 * r28182;
        double r28184 = 2.0;
        double r28185 = a;
        double r28186 = r28177 / r28185;
        double r28187 = r28184 * r28186;
        double r28188 = r28183 - r28187;
        double r28189 = -1.5120874391809866e-204;
        bool r28190 = r28177 <= r28189;
        double r28191 = -r28177;
        double r28192 = r28177 * r28177;
        double r28193 = r28185 * r28181;
        double r28194 = r28192 - r28193;
        double r28195 = sqrt(r28194);
        double r28196 = r28191 + r28195;
        double r28197 = 1.0;
        double r28198 = r28197 / r28185;
        double r28199 = r28196 * r28198;
        double r28200 = 0.023173574830720484;
        bool r28201 = r28177 <= r28200;
        double r28202 = r28191 - r28195;
        double r28203 = r28202 / r28185;
        double r28204 = r28203 / r28181;
        double r28205 = r28197 / r28204;
        double r28206 = r28205 / r28185;
        double r28207 = 4.6383712677255495e+30;
        bool r28208 = r28177 <= r28207;
        double r28209 = -0.5;
        double r28210 = r28209 * r28182;
        double r28211 = 2.292661527341346e+122;
        bool r28212 = r28177 <= r28211;
        double r28213 = 0.0;
        double r28214 = r28213 + r28193;
        double r28215 = r28214 / r28202;
        double r28216 = r28215 / r28185;
        double r28217 = r28212 ? r28216 : r28210;
        double r28218 = r28208 ? r28210 : r28217;
        double r28219 = r28201 ? r28206 : r28218;
        double r28220 = r28190 ? r28199 : r28219;
        double r28221 = r28179 ? r28188 : r28220;
        return r28221;
}

Error

Bits error versus a

Bits error versus b_2

Bits error versus c

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Split input into 5 regimes
  2. if b_2 < -2.1419401754731713e+130

    1. Initial program 57.2

      \[\frac{\left(-b_2\right) + \sqrt{b_2 \cdot b_2 - a \cdot c}}{a}\]
    2. Taylor expanded around -inf 3.2

      \[\leadsto \color{blue}{\frac{1}{2} \cdot \frac{c}{b_2} - 2 \cdot \frac{b_2}{a}}\]

    if -2.1419401754731713e+130 < b_2 < -1.5120874391809866e-204

    1. Initial program 7.0

      \[\frac{\left(-b_2\right) + \sqrt{b_2 \cdot b_2 - a \cdot c}}{a}\]
    2. Using strategy rm
    3. Applied div-inv7.2

      \[\leadsto \color{blue}{\left(\left(-b_2\right) + \sqrt{b_2 \cdot b_2 - a \cdot c}\right) \cdot \frac{1}{a}}\]

    if -1.5120874391809866e-204 < b_2 < 0.023173574830720484

    1. Initial program 22.0

      \[\frac{\left(-b_2\right) + \sqrt{b_2 \cdot b_2 - a \cdot c}}{a}\]
    2. Using strategy rm
    3. Applied flip-+22.2

      \[\leadsto \frac{\color{blue}{\frac{\left(-b_2\right) \cdot \left(-b_2\right) - \sqrt{b_2 \cdot b_2 - a \cdot c} \cdot \sqrt{b_2 \cdot b_2 - a \cdot c}}{\left(-b_2\right) - \sqrt{b_2 \cdot b_2 - a \cdot c}}}}{a}\]
    4. Simplified17.0

      \[\leadsto \frac{\frac{\color{blue}{0 + a \cdot c}}{\left(-b_2\right) - \sqrt{b_2 \cdot b_2 - a \cdot c}}}{a}\]
    5. Using strategy rm
    6. Applied clear-num17.0

      \[\leadsto \frac{\color{blue}{\frac{1}{\frac{\left(-b_2\right) - \sqrt{b_2 \cdot b_2 - a \cdot c}}{0 + a \cdot c}}}}{a}\]
    7. Simplified14.6

      \[\leadsto \frac{\frac{1}{\color{blue}{\frac{\frac{\left(-b_2\right) - \sqrt{b_2 \cdot b_2 - a \cdot c}}{a}}{c}}}}{a}\]

    if 0.023173574830720484 < b_2 < 4.6383712677255495e+30 or 2.292661527341346e+122 < b_2

    1. Initial program 59.4

      \[\frac{\left(-b_2\right) + \sqrt{b_2 \cdot b_2 - a \cdot c}}{a}\]
    2. Taylor expanded around inf 4.1

      \[\leadsto \color{blue}{\frac{-1}{2} \cdot \frac{c}{b_2}}\]

    if 4.6383712677255495e+30 < b_2 < 2.292661527341346e+122

    1. Initial program 47.1

      \[\frac{\left(-b_2\right) + \sqrt{b_2 \cdot b_2 - a \cdot c}}{a}\]
    2. Using strategy rm
    3. Applied flip-+47.1

      \[\leadsto \frac{\color{blue}{\frac{\left(-b_2\right) \cdot \left(-b_2\right) - \sqrt{b_2 \cdot b_2 - a \cdot c} \cdot \sqrt{b_2 \cdot b_2 - a \cdot c}}{\left(-b_2\right) - \sqrt{b_2 \cdot b_2 - a \cdot c}}}}{a}\]
    4. Simplified13.9

      \[\leadsto \frac{\frac{\color{blue}{0 + a \cdot c}}{\left(-b_2\right) - \sqrt{b_2 \cdot b_2 - a \cdot c}}}{a}\]
  3. Recombined 5 regimes into one program.
  4. Final simplification8.6

    \[\leadsto \begin{array}{l} \mathbf{if}\;b_2 \le -2.14194017547317126 \cdot 10^{130}:\\ \;\;\;\;\frac{1}{2} \cdot \frac{c}{b_2} - 2 \cdot \frac{b_2}{a}\\ \mathbf{elif}\;b_2 \le -1.5120874391809866 \cdot 10^{-204}:\\ \;\;\;\;\left(\left(-b_2\right) + \sqrt{b_2 \cdot b_2 - a \cdot c}\right) \cdot \frac{1}{a}\\ \mathbf{elif}\;b_2 \le 0.0231735748307204843:\\ \;\;\;\;\frac{\frac{1}{\frac{\frac{\left(-b_2\right) - \sqrt{b_2 \cdot b_2 - a \cdot c}}{a}}{c}}}{a}\\ \mathbf{elif}\;b_2 \le 4.6383712677255495 \cdot 10^{30}:\\ \;\;\;\;\frac{-1}{2} \cdot \frac{c}{b_2}\\ \mathbf{elif}\;b_2 \le 2.29266152734135 \cdot 10^{122}:\\ \;\;\;\;\frac{\frac{0 + a \cdot c}{\left(-b_2\right) - \sqrt{b_2 \cdot b_2 - a \cdot c}}}{a}\\ \mathbf{else}:\\ \;\;\;\;\frac{-1}{2} \cdot \frac{c}{b_2}\\ \end{array}\]

Reproduce

herbie shell --seed 2020036 
(FPCore (a b_2 c)
  :name "quad2p (problem 3.2.1, positive)"
  :precision binary64
  (/ (+ (- b_2) (sqrt (- (* b_2 b_2) (* a c)))) a))