Average Error: 0.0 → 0.0
Time: 679.0ms
Precision: 64
\[e^{\left(x \cdot y\right) \cdot y}\]
↓
\[e^{\left(x \cdot y\right) \cdot y}\]
e^{\left(x \cdot y\right) \cdot y}
↓
e^{\left(x \cdot y\right) \cdot y}
double f(double x, double y) {
        double r226299 = x;
        double r226300 = y;
        double r226301 = r226299 * r226300;
        double r226302 = r226301 * r226300;
        double r226303 = exp(r226302);
        return r226303;
}
↓
double f(double x, double y) {
        double r226304 = x;
        double r226305 = y;
        double r226306 = r226304 * r226305;
        double r226307 = r226306 * r226305;
        double r226308 = exp(r226307);
        return r226308;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[e^{\left(x \cdot y\right) \cdot y}\]

  2. Final simplification0.0

    \[\leadsto e^{\left(x \cdot y\right) \cdot y}\]

Reproduce

herbie shell --seed 2020036 +o rules:numerics
(FPCore (x y)
  :name "Data.Random.Distribution.Normal:normalF from random-fu-0.2.6.2"
  :precision binary64
  (exp (* (* x y) y)))