Average Error: 0.0 → 0.0
Time: 1.0s
Precision: 64
\[x \cdot \left(y + 1\right)\]
\[x \cdot \left(y + 1\right)\]
x \cdot \left(y + 1\right)
x \cdot \left(y + 1\right)
double f(double x, double y) {
        double r857709 = x;
        double r857710 = y;
        double r857711 = 1.0;
        double r857712 = r857710 + r857711;
        double r857713 = r857709 * r857712;
        return r857713;
}

double f(double x, double y) {
        double r857714 = x;
        double r857715 = y;
        double r857716 = 1.0;
        double r857717 = r857715 + r857716;
        double r857718 = r857714 * r857717;
        return r857718;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.0
Target0.0
Herbie0.0
\[x + x \cdot y\]

Derivation

  1. Initial program 0.0

    \[x \cdot \left(y + 1\right)\]
  2. Final simplification0.0

    \[\leadsto x \cdot \left(y + 1\right)\]

Reproduce

herbie shell --seed 2020035 +o rules:numerics
(FPCore (x y)
  :name "Data.Colour.RGBSpace.HSL:hsl from colour-2.3.3, B"
  :precision binary64

  :herbie-target
  (+ x (* x y))

  (* x (+ y 1)))