\frac{\tan^{-1}_* \frac{im}{re}}{\log 10}\frac{1}{\sqrt{\log 10}} \cdot \left(\left(\left(\tan^{-1}_* \frac{im}{re} \cdot \sqrt{\frac{1}{\sqrt{\log 10}}}\right) \cdot \sqrt{\sqrt{\frac{\sqrt{1}}{\sqrt{\log 10}}}}\right) \cdot \sqrt{\sqrt{\frac{\sqrt{1}}{\sqrt{\log 10}}}}\right)double f(double re, double im) {
double r26273 = im;
double r26274 = re;
double r26275 = atan2(r26273, r26274);
double r26276 = 10.0;
double r26277 = log(r26276);
double r26278 = r26275 / r26277;
return r26278;
}
double f(double re, double im) {
double r26279 = 1.0;
double r26280 = 10.0;
double r26281 = log(r26280);
double r26282 = sqrt(r26281);
double r26283 = r26279 / r26282;
double r26284 = im;
double r26285 = re;
double r26286 = atan2(r26284, r26285);
double r26287 = sqrt(r26283);
double r26288 = r26286 * r26287;
double r26289 = sqrt(r26279);
double r26290 = r26289 / r26282;
double r26291 = sqrt(r26290);
double r26292 = sqrt(r26291);
double r26293 = r26288 * r26292;
double r26294 = r26293 * r26292;
double r26295 = r26283 * r26294;
return r26295;
}



Bits error versus re



Bits error versus im
Results
Initial program 0.8
rmApplied add-sqr-sqrt0.8
Applied *-un-lft-identity0.8
Applied times-frac0.8
Taylor expanded around 0 0.8
rmApplied add-sqr-sqrt0.8
Applied add-sqr-sqrt0.8
Applied times-frac0.8
Applied sqrt-prod0.8
Applied associate-*r*0.8
Simplified0.8
rmApplied add-sqr-sqrt0.8
Applied sqrt-prod0.1
Applied associate-*r*0.1
Final simplification0.1
herbie shell --seed 2020034 +o rules:numerics
(FPCore (re im)
:name "math.log10 on complex, imaginary part"
:precision binary64
(/ (atan2 im re) (log 10)))