Average Error: 0.0 → 0.0
Time: 967.0ms
Precision: 64
\[e^{\left(x \cdot y\right) \cdot y}\]
\[e^{\left(x \cdot y\right) \cdot y}\]
e^{\left(x \cdot y\right) \cdot y}
e^{\left(x \cdot y\right) \cdot y}
double f(double x, double y) {
        double r285718 = x;
        double r285719 = y;
        double r285720 = r285718 * r285719;
        double r285721 = r285720 * r285719;
        double r285722 = exp(r285721);
        return r285722;
}

double f(double x, double y) {
        double r285723 = x;
        double r285724 = y;
        double r285725 = r285723 * r285724;
        double r285726 = r285725 * r285724;
        double r285727 = exp(r285726);
        return r285727;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[e^{\left(x \cdot y\right) \cdot y}\]
  2. Final simplification0.0

    \[\leadsto e^{\left(x \cdot y\right) \cdot y}\]

Reproduce

herbie shell --seed 2020034 +o rules:numerics
(FPCore (x y)
  :name "Data.Random.Distribution.Normal:normalF from random-fu-0.2.6.2"
  :precision binary64
  (exp (* (* x y) y)))