Average Error: 0.0 → 0.0
Time: 1.1s
Precision: 64
\[x \cdot \left(y + 1\right)\]
↓
\[x \cdot \left(y + 1\right)\]
x \cdot \left(y + 1\right)
↓
x \cdot \left(y + 1\right)
double f(double x, double y) {
        double r809548 = x;
        double r809549 = y;
        double r809550 = 1.0;
        double r809551 = r809549 + r809550;
        double r809552 = r809548 * r809551;
        return r809552;
}
↓
double f(double x, double y) {
        double r809553 = x;
        double r809554 = y;
        double r809555 = 1.0;
        double r809556 = r809554 + r809555;
        double r809557 = r809553 * r809556;
        return r809557;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.0
Target0.0
Herbie0.0
\[x + x \cdot y\]

Derivation

  1. Initial program 0.0

    \[x \cdot \left(y + 1\right)\]

  2. Final simplification0.0

    \[\leadsto x \cdot \left(y + 1\right)\]

Reproduce

herbie shell --seed 2020034 
(FPCore (x y)
  :name "Data.Colour.RGBSpace.HSL:hsl from colour-2.3.3, B"
  :precision binary64

  :herbie-target
  (+ x (* x y))

  (* x (+ y 1)))