Average Error: 0.3 → 0.3
Time: 1.5s
Precision: 64
\[\left(x \cdot 27\right) \cdot y\]
↓
\[\left(x \cdot 27\right) \cdot y\]
\left(x \cdot 27\right) \cdot y
↓
\left(x \cdot 27\right) \cdot y
double f(double x, double y) {
        double r247114 = x;
        double r247115 = 27.0;
        double r247116 = r247114 * r247115;
        double r247117 = y;
        double r247118 = r247116 * r247117;
        return r247118;
}
↓
double f(double x, double y) {
        double r247119 = x;
        double r247120 = 27.0;
        double r247121 = r247119 * r247120;
        double r247122 = y;
        double r247123 = r247121 * r247122;
        return r247123;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.3

    \[\left(x \cdot 27\right) \cdot y\]

  2. Final simplification0.3

    \[\leadsto \left(x \cdot 27\right) \cdot y\]

Reproduce

herbie shell --seed 2020027 +o rules:numerics
(FPCore (x y)
  :name "Diagrams.Solve.Polynomial:cubForm  from diagrams-solve-0.1, F"
  :precision binary64
  (* (* x 27) y))