\left(\left(x \cdot y + \frac{z \cdot t}{16}\right) - \frac{a \cdot b}{4}\right) + c\mathsf{fma}\left(z, \frac{t}{16}, \mathsf{fma}\left(y, x, \mathsf{fma}\left(-\frac{a}{4}, b, c\right)\right)\right)double f(double x, double y, double z, double t, double a, double b, double c) {
double r217059 = x;
double r217060 = y;
double r217061 = r217059 * r217060;
double r217062 = z;
double r217063 = t;
double r217064 = r217062 * r217063;
double r217065 = 16.0;
double r217066 = r217064 / r217065;
double r217067 = r217061 + r217066;
double r217068 = a;
double r217069 = b;
double r217070 = r217068 * r217069;
double r217071 = 4.0;
double r217072 = r217070 / r217071;
double r217073 = r217067 - r217072;
double r217074 = c;
double r217075 = r217073 + r217074;
return r217075;
}
double f(double x, double y, double z, double t, double a, double b, double c) {
double r217076 = z;
double r217077 = t;
double r217078 = 16.0;
double r217079 = r217077 / r217078;
double r217080 = y;
double r217081 = x;
double r217082 = a;
double r217083 = 4.0;
double r217084 = r217082 / r217083;
double r217085 = -r217084;
double r217086 = b;
double r217087 = c;
double r217088 = fma(r217085, r217086, r217087);
double r217089 = fma(r217080, r217081, r217088);
double r217090 = fma(r217076, r217079, r217089);
return r217090;
}



Bits error versus x



Bits error versus y



Bits error versus z



Bits error versus t



Bits error versus a



Bits error versus b



Bits error versus c
Initial program 0.1
Simplified0.0
Final simplification0.0
herbie shell --seed 2020027 +o rules:numerics
(FPCore (x y z t a b c)
:name "Diagrams.Solve.Polynomial:quartForm from diagrams-solve-0.1, C"
:precision binary64
(+ (- (+ (* x y) (/ (* z t) 16)) (/ (* a b) 4)) c))