\left(1 + x\right) - x
1
double f(double x) {
double r64 = 1.0;
double r65 = x;
double r66 = r64 + r65;
double r67 = r66 - r65;
return r67;
}
double f(double __attribute__((unused)) x) {
double r68 = 1.0;
return r68;
}



Bits error versus x
Results
Initial program 30.0
Simplified0
Final simplification0
herbie shell --seed 2020025 +o rules:numerics
(FPCore (x)
:name "Cancel like terms"
:precision binary64
(- (+ 1 x) x))