Average Error: 0.0 → 0.0
Time: 2.0s
Precision: 64
\[x \cdot \left(1 - x \cdot 0.5\right)\]
↓
\[x \cdot \left(1 - x \cdot 0.5\right)\]
x \cdot \left(1 - x \cdot 0.5\right)
↓
x \cdot \left(1 - x \cdot 0.5\right)
double f(double x) {
        double r344 = x;
        double r345 = 1.0;
        double r346 = 0.5;
        double r347 = r344 * r346;
        double r348 = r345 - r347;
        double r349 = r344 * r348;
        return r349;
}
↓
double f(double x) {
        double r350 = x;
        double r351 = 1.0;
        double r352 = 0.5;
        double r353 = r350 * r352;
        double r354 = r351 - r353;
        double r355 = r350 * r354;
        return r355;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[x \cdot \left(1 - x \cdot 0.5\right)\]

  2. Final simplification0.0

    \[\leadsto x \cdot \left(1 - x \cdot 0.5\right)\]

Reproduce

herbie shell --seed 2020025 +o rules:numerics
(FPCore (x)
  :name "Numeric.SpecFunctions:log1p from math-functions-0.1.5.2, B"
  :precision binary64
  (* x (- 1 (* x 0.5))))