Average Error: 38.3 → 0.0
Time: 2.1s
Precision: 64
\[\left(x + 1\right) \cdot \left(x + 1\right) - 1\]
\[x \cdot \left(2 + x\right)\]
\left(x + 1\right) \cdot \left(x + 1\right) - 1
x \cdot \left(2 + x\right)
double f(double x) {
        double r64 = x;
        double r65 = 1.0;
        double r66 = r64 + r65;
        double r67 = r66 * r66;
        double r68 = r67 - r65;
        return r68;
}

double f(double x) {
        double r69 = x;
        double r70 = 2.0;
        double r71 = r70 + r69;
        double r72 = r69 * r71;
        return r72;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 38.3

    \[\left(x + 1\right) \cdot \left(x + 1\right) - 1\]
  2. Taylor expanded around 0 0.0

    \[\leadsto \color{blue}{{x}^{2} + 2 \cdot x}\]
  3. Simplified0.0

    \[\leadsto \color{blue}{x \cdot \left(2 + x\right)}\]
  4. Final simplification0.0

    \[\leadsto x \cdot \left(2 + x\right)\]

Reproduce

herbie shell --seed 2020025 
(FPCore (x)
  :name "Expanding a square"
  :precision binary64
  (- (* (+ x 1) (+ x 1)) 1))