Average Error: 0.0 → 0.0
Time: 869.0ms
Precision: 64
\[x \cdot \left(1 - x \cdot 0.5\right)\]
↓
\[x \cdot \left(1 - x \cdot 0.5\right)\]
x \cdot \left(1 - x \cdot 0.5\right)
↓
x \cdot \left(1 - x \cdot 0.5\right)
double f(double x) {
        double r29522 = x;
        double r29523 = 1.0;
        double r29524 = 0.5;
        double r29525 = r29522 * r29524;
        double r29526 = r29523 - r29525;
        double r29527 = r29522 * r29526;
        return r29527;
}
↓
double f(double x) {
        double r29528 = x;
        double r29529 = 1.0;
        double r29530 = 0.5;
        double r29531 = r29528 * r29530;
        double r29532 = r29529 - r29531;
        double r29533 = r29528 * r29532;
        return r29533;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[x \cdot \left(1 - x \cdot 0.5\right)\]

  2. Final simplification0.0

    \[\leadsto x \cdot \left(1 - x \cdot 0.5\right)\]

Reproduce

herbie shell --seed 2020024 +o rules:numerics
(FPCore (x)
  :name "Numeric.SpecFunctions:log1p from math-functions-0.1.5.2, B"
  :precision binary64
  (* x (- 1 (* x 0.5))))