Average Error: 0.0 → 0.0
Time: 766.0ms
Precision: 64
\[x \cdot \left(y + 1\right)\]
\[x \cdot \left(y + 1\right)\]
x \cdot \left(y + 1\right)
x \cdot \left(y + 1\right)
double f(double x, double y) {
        double r951855 = x;
        double r951856 = y;
        double r951857 = 1.0;
        double r951858 = r951856 + r951857;
        double r951859 = r951855 * r951858;
        return r951859;
}

double f(double x, double y) {
        double r951860 = x;
        double r951861 = y;
        double r951862 = 1.0;
        double r951863 = r951861 + r951862;
        double r951864 = r951860 * r951863;
        return r951864;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.0
Target0.0
Herbie0.0
\[x + x \cdot y\]

Derivation

  1. Initial program 0.0

    \[x \cdot \left(y + 1\right)\]
  2. Final simplification0.0

    \[\leadsto x \cdot \left(y + 1\right)\]

Reproduce

herbie shell --seed 2020021 +o rules:numerics
(FPCore (x y)
  :name "Data.Colour.RGBSpace.HSL:hsl from colour-2.3.3, B"
  :precision binary64

  :herbie-target
  (+ x (* x y))

  (* x (+ y 1)))