\frac{1 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)}{2 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)}\frac{1 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)}{2 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)}double f(double t) {
double r50881 = 1.0;
double r50882 = 2.0;
double r50883 = t;
double r50884 = r50882 / r50883;
double r50885 = r50881 / r50883;
double r50886 = r50881 + r50885;
double r50887 = r50884 / r50886;
double r50888 = r50882 - r50887;
double r50889 = r50888 * r50888;
double r50890 = r50881 + r50889;
double r50891 = r50882 + r50889;
double r50892 = r50890 / r50891;
return r50892;
}
double f(double t) {
double r50893 = 1.0;
double r50894 = 2.0;
double r50895 = t;
double r50896 = r50894 / r50895;
double r50897 = r50893 / r50895;
double r50898 = r50893 + r50897;
double r50899 = r50896 / r50898;
double r50900 = r50894 - r50899;
double r50901 = r50900 * r50900;
double r50902 = r50893 + r50901;
double r50903 = r50894 + r50901;
double r50904 = r50902 / r50903;
return r50904;
}



Bits error versus t
Results
Initial program 0.0
Final simplification0.0
herbie shell --seed 2020020 +o rules:numerics
(FPCore (t)
:name "Kahan p13 Example 2"
:precision binary64
(/ (+ 1 (* (- 2 (/ (/ 2 t) (+ 1 (/ 1 t)))) (- 2 (/ (/ 2 t) (+ 1 (/ 1 t)))))) (+ 2 (* (- 2 (/ (/ 2 t) (+ 1 (/ 1 t)))) (- 2 (/ (/ 2 t) (+ 1 (/ 1 t))))))))