Average Error: 0.3 → 0.3
Time: 1.2s
Precision: 64
\[\left(x \cdot 27\right) \cdot y\]
\[x \cdot \left(27 \cdot y\right)\]
\left(x \cdot 27\right) \cdot y
x \cdot \left(27 \cdot y\right)
double f(double x, double y) {
        double r280856 = x;
        double r280857 = 27.0;
        double r280858 = r280856 * r280857;
        double r280859 = y;
        double r280860 = r280858 * r280859;
        return r280860;
}

double f(double x, double y) {
        double r280861 = x;
        double r280862 = 27.0;
        double r280863 = y;
        double r280864 = r280862 * r280863;
        double r280865 = r280861 * r280864;
        return r280865;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.3

    \[\left(x \cdot 27\right) \cdot y\]
  2. Using strategy rm
  3. Applied associate-*l*0.3

    \[\leadsto \color{blue}{x \cdot \left(27 \cdot y\right)}\]
  4. Final simplification0.3

    \[\leadsto x \cdot \left(27 \cdot y\right)\]

Reproduce

herbie shell --seed 2020020 +o rules:numerics
(FPCore (x y)
  :name "Diagrams.Solve.Polynomial:cubForm  from diagrams-solve-0.1, F"
  :precision binary64
  (* (* x 27) y))