\left(\left(x \cdot y + \frac{z \cdot t}{16}\right) - \frac{a \cdot b}{4}\right) + c\mathsf{fma}\left(z, \frac{t}{16}, \mathsf{fma}\left(y, x, \mathsf{fma}\left(-\frac{a}{4}, b, c\right)\right)\right)double f(double x, double y, double z, double t, double a, double b, double c) {
double r165853 = x;
double r165854 = y;
double r165855 = r165853 * r165854;
double r165856 = z;
double r165857 = t;
double r165858 = r165856 * r165857;
double r165859 = 16.0;
double r165860 = r165858 / r165859;
double r165861 = r165855 + r165860;
double r165862 = a;
double r165863 = b;
double r165864 = r165862 * r165863;
double r165865 = 4.0;
double r165866 = r165864 / r165865;
double r165867 = r165861 - r165866;
double r165868 = c;
double r165869 = r165867 + r165868;
return r165869;
}
double f(double x, double y, double z, double t, double a, double b, double c) {
double r165870 = z;
double r165871 = t;
double r165872 = 16.0;
double r165873 = r165871 / r165872;
double r165874 = y;
double r165875 = x;
double r165876 = a;
double r165877 = 4.0;
double r165878 = r165876 / r165877;
double r165879 = -r165878;
double r165880 = b;
double r165881 = c;
double r165882 = fma(r165879, r165880, r165881);
double r165883 = fma(r165874, r165875, r165882);
double r165884 = fma(r165870, r165873, r165883);
return r165884;
}



Bits error versus x



Bits error versus y



Bits error versus z



Bits error versus t



Bits error versus a



Bits error versus b



Bits error versus c
Initial program 0.1
Simplified0.0
Final simplification0.0
herbie shell --seed 2020020 +o rules:numerics
(FPCore (x y z t a b c)
:name "Diagrams.Solve.Polynomial:quartForm from diagrams-solve-0.1, C"
:precision binary64
(+ (- (+ (* x y) (/ (* z t) 16)) (/ (* a b) 4)) c))