Average Error: 0.0 → 0.0
Time: 1.2s
Precision: 64
\[e^{\left(x \cdot y\right) \cdot y}\]
\[e^{\left(x \cdot y\right) \cdot y}\]
e^{\left(x \cdot y\right) \cdot y}
e^{\left(x \cdot y\right) \cdot y}
double f(double x, double y) {
        double r200689 = x;
        double r200690 = y;
        double r200691 = r200689 * r200690;
        double r200692 = r200691 * r200690;
        double r200693 = exp(r200692);
        return r200693;
}

double f(double x, double y) {
        double r200694 = x;
        double r200695 = y;
        double r200696 = r200694 * r200695;
        double r200697 = r200696 * r200695;
        double r200698 = exp(r200697);
        return r200698;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[e^{\left(x \cdot y\right) \cdot y}\]
  2. Final simplification0.0

    \[\leadsto e^{\left(x \cdot y\right) \cdot y}\]

Reproduce

herbie shell --seed 2020018 +o rules:numerics
(FPCore (x y)
  :name "Data.Random.Distribution.Normal:normalF from random-fu-0.2.6.2"
  :precision binary64
  (exp (* (* x y) y)))