\left(\left(x \cdot y + \frac{z \cdot t}{16}\right) - \frac{a \cdot b}{4}\right) + c\mathsf{fma}\left(z, \frac{t}{16}, \mathsf{fma}\left(y, x, \mathsf{fma}\left(-\frac{a}{4}, b, c\right)\right)\right)double f(double x, double y, double z, double t, double a, double b, double c) {
double r198267 = x;
double r198268 = y;
double r198269 = r198267 * r198268;
double r198270 = z;
double r198271 = t;
double r198272 = r198270 * r198271;
double r198273 = 16.0;
double r198274 = r198272 / r198273;
double r198275 = r198269 + r198274;
double r198276 = a;
double r198277 = b;
double r198278 = r198276 * r198277;
double r198279 = 4.0;
double r198280 = r198278 / r198279;
double r198281 = r198275 - r198280;
double r198282 = c;
double r198283 = r198281 + r198282;
return r198283;
}
double f(double x, double y, double z, double t, double a, double b, double c) {
double r198284 = z;
double r198285 = t;
double r198286 = 16.0;
double r198287 = r198285 / r198286;
double r198288 = y;
double r198289 = x;
double r198290 = a;
double r198291 = 4.0;
double r198292 = r198290 / r198291;
double r198293 = -r198292;
double r198294 = b;
double r198295 = c;
double r198296 = fma(r198293, r198294, r198295);
double r198297 = fma(r198288, r198289, r198296);
double r198298 = fma(r198284, r198287, r198297);
return r198298;
}



Bits error versus x



Bits error versus y



Bits error versus z



Bits error versus t



Bits error versus a



Bits error versus b



Bits error versus c
Initial program 0.1
Simplified0.0
Final simplification0.0
herbie shell --seed 2020018 +o rules:numerics
(FPCore (x y z t a b c)
:name "Diagrams.Solve.Polynomial:quartForm from diagrams-solve-0.1, C"
:precision binary64
(+ (- (+ (* x y) (/ (* z t) 16)) (/ (* a b) 4)) c))