Average Error: 0 → 0
Time: 328.0ms
Precision: 64
\[\left(x \cdot 2\right) \cdot x\]
↓
\[\left(x \cdot 2\right) \cdot x\]
\left(x \cdot 2\right) \cdot x
↓
\left(x \cdot 2\right) \cdot x
double f(double x) {
        double r442802 = x;
        double r442803 = 2.0;
        double r442804 = r442802 * r442803;
        double r442805 = r442804 * r442802;
        return r442805;
}
↓
double f(double x) {
        double r442806 = x;
        double r442807 = 2.0;
        double r442808 = r442806 * r442807;
        double r442809 = r442808 * r442806;
        return r442809;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0
Target0
Herbie0
\[\left(2 \cdot x\right) \cdot x\]

Derivation

  1. Initial program 0

    \[\left(x \cdot 2\right) \cdot x\]

  2. Final simplification0

    \[\leadsto \left(x \cdot 2\right) \cdot x\]

Reproduce

herbie shell --seed 2020018 +o rules:numerics
(FPCore (x)
  :name "Numeric.Log:$cexpm1 from log-domain-0.10.2.1, A"
  :precision binary64

  :herbie-target
  (* (* 2 x) x)

  (* (* x 2) x))