Average Error: 0.1 → 0
Time: 806.0ms
Precision: 64
\[\left(d1 \cdot \left(\left(\left(\left(\left(d1 \cdot \left(d1 \cdot d1\right)\right) \cdot d1\right) \cdot d1\right) \cdot \left(d1 \cdot d1\right)\right) \cdot d1\right)\right) \cdot d1\]
↓
\[{d1}^{10}\]
\left(d1 \cdot \left(\left(\left(\left(\left(d1 \cdot \left(d1 \cdot d1\right)\right) \cdot d1\right) \cdot d1\right) \cdot \left(d1 \cdot d1\right)\right) \cdot d1\right)\right) \cdot d1
↓
{d1}^{10}
double f(double d1) {
        double r140837 = d1;
        double r140838 = r140837 * r140837;
        double r140839 = r140837 * r140838;
        double r140840 = r140839 * r140837;
        double r140841 = r140840 * r140837;
        double r140842 = r140841 * r140838;
        double r140843 = r140842 * r140837;
        double r140844 = r140837 * r140843;
        double r140845 = r140844 * r140837;
        return r140845;
}
↓
double f(double d1) {
        double r140846 = d1;
        double r140847 = 10.0;
        double r140848 = pow(r140846, r140847);
        return r140848;
}

Error

Bits error versus d1

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.1
Target0
Herbie0
\[{d1}^{10}\]

Derivation

  1. Initial program 0.1

    \[\left(d1 \cdot \left(\left(\left(\left(\left(d1 \cdot \left(d1 \cdot d1\right)\right) \cdot d1\right) \cdot d1\right) \cdot \left(d1 \cdot d1\right)\right) \cdot d1\right)\right) \cdot d1\]

  2. Simplified0

    \[\leadsto \color{blue}{{d1}^{10}}\]

  3. Final simplification0

    \[\leadsto {d1}^{10}\]

Reproduce

herbie shell --seed 2020018 
(FPCore (d1)
  :name "FastMath test5"
  :precision binary64

  :herbie-target
  (pow d1 10)

  (* (* d1 (* (* (* (* (* d1 (* d1 d1)) d1) d1) (* d1 d1)) d1)) d1))