Average Error: 29.4 → 22.0
Time: 9.6s
Precision: 64
\[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)}\]
\[\begin{array}{l} \mathbf{if}\;n \le -13450.5463236965716:\\ \;\;\;\;\frac{\frac{1}{n}}{x} - \left(\log \left(e^{\frac{0.5}{{x}^{2} \cdot n}}\right) - \frac{\log x \cdot 1}{x \cdot {n}^{2}}\right)\\ \mathbf{elif}\;n \le 1358332.53943660879:\\ \;\;\;\;\log \left(e^{{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)}}\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{1}{n}}{x} - \left(\frac{\frac{0.5}{n}}{{x}^{2}} - \frac{\frac{\log x \cdot 1}{x}}{{n}^{2}}\right)\\ \end{array}\]
{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)}
\begin{array}{l}
\mathbf{if}\;n \le -13450.5463236965716:\\
\;\;\;\;\frac{\frac{1}{n}}{x} - \left(\log \left(e^{\frac{0.5}{{x}^{2} \cdot n}}\right) - \frac{\log x \cdot 1}{x \cdot {n}^{2}}\right)\\

\mathbf{elif}\;n \le 1358332.53943660879:\\
\;\;\;\;\log \left(e^{{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)}}\right)\\

\mathbf{else}:\\
\;\;\;\;\frac{\frac{1}{n}}{x} - \left(\frac{\frac{0.5}{n}}{{x}^{2}} - \frac{\frac{\log x \cdot 1}{x}}{{n}^{2}}\right)\\

\end{array}
double f(double x, double n) {
        double r38842 = x;
        double r38843 = 1.0;
        double r38844 = r38842 + r38843;
        double r38845 = n;
        double r38846 = r38843 / r38845;
        double r38847 = pow(r38844, r38846);
        double r38848 = pow(r38842, r38846);
        double r38849 = r38847 - r38848;
        return r38849;
}

double f(double x, double n) {
        double r38850 = n;
        double r38851 = -13450.546323696572;
        bool r38852 = r38850 <= r38851;
        double r38853 = 1.0;
        double r38854 = r38853 / r38850;
        double r38855 = x;
        double r38856 = r38854 / r38855;
        double r38857 = 0.5;
        double r38858 = 2.0;
        double r38859 = pow(r38855, r38858);
        double r38860 = r38859 * r38850;
        double r38861 = r38857 / r38860;
        double r38862 = exp(r38861);
        double r38863 = log(r38862);
        double r38864 = log(r38855);
        double r38865 = r38864 * r38853;
        double r38866 = pow(r38850, r38858);
        double r38867 = r38855 * r38866;
        double r38868 = r38865 / r38867;
        double r38869 = r38863 - r38868;
        double r38870 = r38856 - r38869;
        double r38871 = 1358332.5394366088;
        bool r38872 = r38850 <= r38871;
        double r38873 = r38855 + r38853;
        double r38874 = pow(r38873, r38854);
        double r38875 = pow(r38855, r38854);
        double r38876 = r38874 - r38875;
        double r38877 = exp(r38876);
        double r38878 = log(r38877);
        double r38879 = r38857 / r38850;
        double r38880 = r38879 / r38859;
        double r38881 = r38865 / r38855;
        double r38882 = r38881 / r38866;
        double r38883 = r38880 - r38882;
        double r38884 = r38856 - r38883;
        double r38885 = r38872 ? r38878 : r38884;
        double r38886 = r38852 ? r38870 : r38885;
        return r38886;
}

Error

Bits error versus x

Bits error versus n

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Split input into 3 regimes
  2. if n < -13450.546323696572

    1. Initial program 44.8

      \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)}\]
    2. Taylor expanded around inf 32.2

      \[\leadsto \color{blue}{1 \cdot \frac{1}{x \cdot n} - \left(0.5 \cdot \frac{1}{{x}^{2} \cdot n} + 1 \cdot \frac{\log \left(\frac{1}{x}\right)}{x \cdot {n}^{2}}\right)}\]
    3. Simplified31.4

      \[\leadsto \color{blue}{\frac{\frac{1}{n}}{x} - \left(\frac{\frac{0.5}{n}}{{x}^{2}} - \frac{\log x \cdot 1}{x \cdot {n}^{2}}\right)}\]
    4. Using strategy rm
    5. Applied add-log-exp31.5

      \[\leadsto \frac{\frac{1}{n}}{x} - \left(\color{blue}{\log \left(e^{\frac{\frac{0.5}{n}}{{x}^{2}}}\right)} - \frac{\log x \cdot 1}{x \cdot {n}^{2}}\right)\]
    6. Simplified31.5

      \[\leadsto \frac{\frac{1}{n}}{x} - \left(\log \color{blue}{\left(e^{\frac{0.5}{{x}^{2} \cdot n}}\right)} - \frac{\log x \cdot 1}{x \cdot {n}^{2}}\right)\]

    if -13450.546323696572 < n < 1358332.5394366088

    1. Initial program 8.2

      \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)}\]
    2. Using strategy rm
    3. Applied add-log-exp8.5

      \[\leadsto {\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - \color{blue}{\log \left(e^{{x}^{\left(\frac{1}{n}\right)}}\right)}\]
    4. Applied add-log-exp8.4

      \[\leadsto \color{blue}{\log \left(e^{{\left(x + 1\right)}^{\left(\frac{1}{n}\right)}}\right)} - \log \left(e^{{x}^{\left(\frac{1}{n}\right)}}\right)\]
    5. Applied diff-log8.4

      \[\leadsto \color{blue}{\log \left(\frac{e^{{\left(x + 1\right)}^{\left(\frac{1}{n}\right)}}}{e^{{x}^{\left(\frac{1}{n}\right)}}}\right)}\]
    6. Simplified8.4

      \[\leadsto \log \color{blue}{\left(e^{{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)}}\right)}\]

    if 1358332.5394366088 < n

    1. Initial program 44.9

      \[{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)}\]
    2. Taylor expanded around inf 33.2

      \[\leadsto \color{blue}{1 \cdot \frac{1}{x \cdot n} - \left(0.5 \cdot \frac{1}{{x}^{2} \cdot n} + 1 \cdot \frac{\log \left(\frac{1}{x}\right)}{x \cdot {n}^{2}}\right)}\]
    3. Simplified32.4

      \[\leadsto \color{blue}{\frac{\frac{1}{n}}{x} - \left(\frac{\frac{0.5}{n}}{{x}^{2}} - \frac{\log x \cdot 1}{x \cdot {n}^{2}}\right)}\]
    4. Using strategy rm
    5. Applied associate-/r*32.4

      \[\leadsto \frac{\frac{1}{n}}{x} - \left(\frac{\frac{0.5}{n}}{{x}^{2}} - \color{blue}{\frac{\frac{\log x \cdot 1}{x}}{{n}^{2}}}\right)\]
  3. Recombined 3 regimes into one program.
  4. Final simplification22.0

    \[\leadsto \begin{array}{l} \mathbf{if}\;n \le -13450.5463236965716:\\ \;\;\;\;\frac{\frac{1}{n}}{x} - \left(\log \left(e^{\frac{0.5}{{x}^{2} \cdot n}}\right) - \frac{\log x \cdot 1}{x \cdot {n}^{2}}\right)\\ \mathbf{elif}\;n \le 1358332.53943660879:\\ \;\;\;\;\log \left(e^{{\left(x + 1\right)}^{\left(\frac{1}{n}\right)} - {x}^{\left(\frac{1}{n}\right)}}\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{1}{n}}{x} - \left(\frac{\frac{0.5}{n}}{{x}^{2}} - \frac{\frac{\log x \cdot 1}{x}}{{n}^{2}}\right)\\ \end{array}\]

Reproduce

herbie shell --seed 2020018 
(FPCore (x n)
  :name "2nthrt (problem 3.4.6)"
  :precision binary64
  (- (pow (+ x 1) (/ 1 n)) (pow x (/ 1 n))))