Average Error: 0.0 → 0.0
Time: 1.7s
Precision: 64
\[\frac{-\left(f + n\right)}{f - n}\]
\[\frac{1}{\frac{f - n}{-\left(f + n\right)}}\]
\frac{-\left(f + n\right)}{f - n}
\frac{1}{\frac{f - n}{-\left(f + n\right)}}
double f(double f, double n) {
        double r4631 = f;
        double r4632 = n;
        double r4633 = r4631 + r4632;
        double r4634 = -r4633;
        double r4635 = r4631 - r4632;
        double r4636 = r4634 / r4635;
        return r4636;
}

double f(double f, double n) {
        double r4637 = 1.0;
        double r4638 = f;
        double r4639 = n;
        double r4640 = r4638 - r4639;
        double r4641 = r4638 + r4639;
        double r4642 = -r4641;
        double r4643 = r4640 / r4642;
        double r4644 = r4637 / r4643;
        return r4644;
}

Error

Bits error versus f

Bits error versus n

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[\frac{-\left(f + n\right)}{f - n}\]
  2. Using strategy rm
  3. Applied clear-num0.0

    \[\leadsto \color{blue}{\frac{1}{\frac{f - n}{-\left(f + n\right)}}}\]
  4. Final simplification0.0

    \[\leadsto \frac{1}{\frac{f - n}{-\left(f + n\right)}}\]

Reproduce

herbie shell --seed 2020003 
(FPCore (f n)
  :name "subtraction fraction"
  :precision binary64
  (/ (- (+ f n)) (- f n)))