Average Error: 53.3 → 0.1
Time: 12.7s
Precision: 64
\[\log \left(x + \sqrt{x \cdot x + 1}\right)\]
\[\begin{array}{l} \mathbf{if}\;x \le -1.010680203662621456928150109888520091772:\\ \;\;\;\;\log \left(\frac{0.125}{{x}^{3}} - \left(\frac{0.5}{x} - \frac{-0.0625}{{x}^{5}}\right)\right)\\ \mathbf{elif}\;x \le 0.001041760398045713442369275547605411702534:\\ \;\;\;\;\left(\log \left(\sqrt{1}\right) + \frac{x}{\sqrt{1}}\right) - \frac{1}{6} \cdot \frac{{x}^{3}}{{\left(\sqrt{1}\right)}^{3}}\\ \mathbf{else}:\\ \;\;\;\;\log \left(1 \cdot \left(\mathsf{hypot}\left(x, \sqrt{1}\right) + x\right)\right)\\ \end{array}\]
\log \left(x + \sqrt{x \cdot x + 1}\right)
\begin{array}{l}
\mathbf{if}\;x \le -1.010680203662621456928150109888520091772:\\
\;\;\;\;\log \left(\frac{0.125}{{x}^{3}} - \left(\frac{0.5}{x} - \frac{-0.0625}{{x}^{5}}\right)\right)\\

\mathbf{elif}\;x \le 0.001041760398045713442369275547605411702534:\\
\;\;\;\;\left(\log \left(\sqrt{1}\right) + \frac{x}{\sqrt{1}}\right) - \frac{1}{6} \cdot \frac{{x}^{3}}{{\left(\sqrt{1}\right)}^{3}}\\

\mathbf{else}:\\
\;\;\;\;\log \left(1 \cdot \left(\mathsf{hypot}\left(x, \sqrt{1}\right) + x\right)\right)\\

\end{array}
double f(double x) {
        double r201614 = x;
        double r201615 = r201614 * r201614;
        double r201616 = 1.0;
        double r201617 = r201615 + r201616;
        double r201618 = sqrt(r201617);
        double r201619 = r201614 + r201618;
        double r201620 = log(r201619);
        return r201620;
}

double f(double x) {
        double r201621 = x;
        double r201622 = -1.0106802036626215;
        bool r201623 = r201621 <= r201622;
        double r201624 = 0.125;
        double r201625 = 3.0;
        double r201626 = pow(r201621, r201625);
        double r201627 = r201624 / r201626;
        double r201628 = 0.5;
        double r201629 = r201628 / r201621;
        double r201630 = 0.0625;
        double r201631 = -r201630;
        double r201632 = 5.0;
        double r201633 = pow(r201621, r201632);
        double r201634 = r201631 / r201633;
        double r201635 = r201629 - r201634;
        double r201636 = r201627 - r201635;
        double r201637 = log(r201636);
        double r201638 = 0.0010417603980457134;
        bool r201639 = r201621 <= r201638;
        double r201640 = 1.0;
        double r201641 = sqrt(r201640);
        double r201642 = log(r201641);
        double r201643 = r201621 / r201641;
        double r201644 = r201642 + r201643;
        double r201645 = 0.16666666666666666;
        double r201646 = pow(r201641, r201625);
        double r201647 = r201626 / r201646;
        double r201648 = r201645 * r201647;
        double r201649 = r201644 - r201648;
        double r201650 = 1.0;
        double r201651 = hypot(r201621, r201641);
        double r201652 = r201651 + r201621;
        double r201653 = r201650 * r201652;
        double r201654 = log(r201653);
        double r201655 = r201639 ? r201649 : r201654;
        double r201656 = r201623 ? r201637 : r201655;
        return r201656;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original53.3
Target45.4
Herbie0.1
\[\begin{array}{l} \mathbf{if}\;x \lt 0.0:\\ \;\;\;\;\log \left(\frac{-1}{x - \sqrt{x \cdot x + 1}}\right)\\ \mathbf{else}:\\ \;\;\;\;\log \left(x + \sqrt{x \cdot x + 1}\right)\\ \end{array}\]

Derivation

  1. Split input into 3 regimes
  2. if x < -1.0106802036626215

    1. Initial program 62.9

      \[\log \left(x + \sqrt{x \cdot x + 1}\right)\]
    2. Taylor expanded around -inf 0.2

      \[\leadsto \log \color{blue}{\left(0.125 \cdot \frac{1}{{x}^{3}} - \left(0.5 \cdot \frac{1}{x} + 0.0625 \cdot \frac{1}{{x}^{5}}\right)\right)}\]
    3. Simplified0.2

      \[\leadsto \log \color{blue}{\left(\frac{0.125}{{x}^{3}} - \left(\frac{0.5}{x} - \frac{-0.0625}{{x}^{5}}\right)\right)}\]

    if -1.0106802036626215 < x < 0.0010417603980457134

    1. Initial program 59.1

      \[\log \left(x + \sqrt{x \cdot x + 1}\right)\]
    2. Taylor expanded around 0 0.1

      \[\leadsto \color{blue}{\left(\log \left(\sqrt{1}\right) + \frac{x}{\sqrt{1}}\right) - \frac{1}{6} \cdot \frac{{x}^{3}}{{\left(\sqrt{1}\right)}^{3}}}\]

    if 0.0010417603980457134 < x

    1. Initial program 31.9

      \[\log \left(x + \sqrt{x \cdot x + 1}\right)\]
    2. Using strategy rm
    3. Applied *-un-lft-identity31.9

      \[\leadsto \log \left(x + \color{blue}{1 \cdot \sqrt{x \cdot x + 1}}\right)\]
    4. Applied *-un-lft-identity31.9

      \[\leadsto \log \left(\color{blue}{1 \cdot x} + 1 \cdot \sqrt{x \cdot x + 1}\right)\]
    5. Applied distribute-lft-out31.9

      \[\leadsto \log \color{blue}{\left(1 \cdot \left(x + \sqrt{x \cdot x + 1}\right)\right)}\]
    6. Simplified0.1

      \[\leadsto \log \left(1 \cdot \color{blue}{\left(\mathsf{hypot}\left(x, \sqrt{1}\right) + x\right)}\right)\]
  3. Recombined 3 regimes into one program.
  4. Final simplification0.1

    \[\leadsto \begin{array}{l} \mathbf{if}\;x \le -1.010680203662621456928150109888520091772:\\ \;\;\;\;\log \left(\frac{0.125}{{x}^{3}} - \left(\frac{0.5}{x} - \frac{-0.0625}{{x}^{5}}\right)\right)\\ \mathbf{elif}\;x \le 0.001041760398045713442369275547605411702534:\\ \;\;\;\;\left(\log \left(\sqrt{1}\right) + \frac{x}{\sqrt{1}}\right) - \frac{1}{6} \cdot \frac{{x}^{3}}{{\left(\sqrt{1}\right)}^{3}}\\ \mathbf{else}:\\ \;\;\;\;\log \left(1 \cdot \left(\mathsf{hypot}\left(x, \sqrt{1}\right) + x\right)\right)\\ \end{array}\]

Reproduce

herbie shell --seed 2020001 +o rules:numerics
(FPCore (x)
  :name "Hyperbolic arcsine"
  :precision binary64

  :herbie-target
  (if (< x 0.0) (log (/ -1 (- x (sqrt (+ (* x x) 1))))) (log (+ x (sqrt (+ (* x x) 1)))))

  (log (+ x (sqrt (+ (* x x) 1)))))