Average Error: 0 → 0
Time: 375.0ms
Precision: 64
\[\left(x \cdot 2\right) \cdot x\]
\[\left(x \cdot 2\right) \cdot x\]
\left(x \cdot 2\right) \cdot x
\left(x \cdot 2\right) \cdot x
double f(double x) {
        double r560361 = x;
        double r560362 = 2.0;
        double r560363 = r560361 * r560362;
        double r560364 = r560363 * r560361;
        return r560364;
}

double f(double x) {
        double r560365 = x;
        double r560366 = 2.0;
        double r560367 = r560365 * r560366;
        double r560368 = r560367 * r560365;
        return r560368;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0
Target0
Herbie0
\[\left(2 \cdot x\right) \cdot x\]

Derivation

  1. Initial program 0

    \[\left(x \cdot 2\right) \cdot x\]
  2. Final simplification0

    \[\leadsto \left(x \cdot 2\right) \cdot x\]

Reproduce

herbie shell --seed 2020001 
(FPCore (x)
  :name "Numeric.Log:$cexpm1 from log-domain-0.10.2.1, A"
  :precision binary64

  :herbie-target
  (* (* 2 x) x)

  (* (* x 2) x))