\frac{1 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)}{2 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)}\frac{1 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)}{2 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)}double f(double t) {
double r50877 = 1.0;
double r50878 = 2.0;
double r50879 = t;
double r50880 = r50878 / r50879;
double r50881 = r50877 / r50879;
double r50882 = r50877 + r50881;
double r50883 = r50880 / r50882;
double r50884 = r50878 - r50883;
double r50885 = r50884 * r50884;
double r50886 = r50877 + r50885;
double r50887 = r50878 + r50885;
double r50888 = r50886 / r50887;
return r50888;
}
double f(double t) {
double r50889 = 1.0;
double r50890 = 2.0;
double r50891 = t;
double r50892 = r50890 / r50891;
double r50893 = r50889 / r50891;
double r50894 = r50889 + r50893;
double r50895 = r50892 / r50894;
double r50896 = r50890 - r50895;
double r50897 = r50896 * r50896;
double r50898 = r50889 + r50897;
double r50899 = r50890 + r50897;
double r50900 = r50898 / r50899;
return r50900;
}



Bits error versus t
Results
Initial program 0.0
Final simplification0.0
herbie shell --seed 2020001
(FPCore (t)
:name "Kahan p13 Example 2"
:precision binary64
(/ (+ 1 (* (- 2 (/ (/ 2 t) (+ 1 (/ 1 t)))) (- 2 (/ (/ 2 t) (+ 1 (/ 1 t)))))) (+ 2 (* (- 2 (/ (/ 2 t) (+ 1 (/ 1 t)))) (- 2 (/ (/ 2 t) (+ 1 (/ 1 t))))))))