Average Error: 5.5 → 5.5
Time: 2.6s
Precision: 64
\[x \cdot \left(1 + y \cdot y\right)\]
↓
\[x \cdot \left(1 + y \cdot y\right)\]
x \cdot \left(1 + y \cdot y\right)
↓
x \cdot \left(1 + y \cdot y\right)
double f(double x, double y) {
        double r428915 = x;
        double r428916 = 1.0;
        double r428917 = y;
        double r428918 = r428917 * r428917;
        double r428919 = r428916 + r428918;
        double r428920 = r428915 * r428919;
        return r428920;
}
↓
double f(double x, double y) {
        double r428921 = x;
        double r428922 = 1.0;
        double r428923 = y;
        double r428924 = r428923 * r428923;
        double r428925 = r428922 + r428924;
        double r428926 = r428921 * r428925;
        return r428926;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original5.5
Target0.1
Herbie5.5
\[x + \left(x \cdot y\right) \cdot y\]

Derivation

  1. Initial program 5.5

    \[x \cdot \left(1 + y \cdot y\right)\]

  2. Final simplification5.5

    \[\leadsto x \cdot \left(1 + y \cdot y\right)\]

Reproduce

herbie shell --seed 2020001 
(FPCore (x y)
  :name "Numeric.Integration.TanhSinh:everywhere from integration-0.2.1"
  :precision binary64

  :herbie-target
  (+ x (* (* x y) y))

  (* x (+ 1 (* y y))))