Average Error: 0.0 → 0.0
Time: 392.0ms
Precision: 64
\[x \cdot \left(1 - x \cdot 0.5\right)\]
↓
\[x \cdot \left(1 - x \cdot 0.5\right)\]
x \cdot \left(1 - x \cdot 0.5\right)
↓
x \cdot \left(1 - x \cdot 0.5\right)
double f(double x) {
        double r72755 = x;
        double r72756 = 1.0;
        double r72757 = 0.5;
        double r72758 = r72755 * r72757;
        double r72759 = r72756 - r72758;
        double r72760 = r72755 * r72759;
        return r72760;
}
↓
double f(double x) {
        double r72761 = x;
        double r72762 = 1.0;
        double r72763 = 0.5;
        double r72764 = r72761 * r72763;
        double r72765 = r72762 - r72764;
        double r72766 = r72761 * r72765;
        return r72766;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[x \cdot \left(1 - x \cdot 0.5\right)\]

  2. Final simplification0.0

    \[\leadsto x \cdot \left(1 - x \cdot 0.5\right)\]

Reproduce

herbie shell --seed 2019362 +o rules:numerics
(FPCore (x)
  :name "Numeric.SpecFunctions:log1p from math-functions-0.1.5.2, B"
  :precision binary64
  (* x (- 1 (* x 0.5))))