1 - \frac{1}{2 + \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right) \cdot \left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}\right)}1 - 1 \cdot \mathsf{log1p}\left(\mathsf{expm1}\left(\frac{1}{\mathsf{fma}\left(2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}, 2 - \frac{\frac{2}{t}}{1 + \frac{1}{t}}, 2\right)}\right)\right)double f(double t) {
double r61259 = 1.0;
double r61260 = 2.0;
double r61261 = t;
double r61262 = r61260 / r61261;
double r61263 = r61259 / r61261;
double r61264 = r61259 + r61263;
double r61265 = r61262 / r61264;
double r61266 = r61260 - r61265;
double r61267 = r61266 * r61266;
double r61268 = r61260 + r61267;
double r61269 = r61259 / r61268;
double r61270 = r61259 - r61269;
return r61270;
}
double f(double t) {
double r61271 = 1.0;
double r61272 = 1.0;
double r61273 = 2.0;
double r61274 = t;
double r61275 = r61273 / r61274;
double r61276 = r61271 / r61274;
double r61277 = r61271 + r61276;
double r61278 = r61275 / r61277;
double r61279 = r61273 - r61278;
double r61280 = fma(r61279, r61279, r61273);
double r61281 = r61271 / r61280;
double r61282 = expm1(r61281);
double r61283 = log1p(r61282);
double r61284 = r61272 * r61283;
double r61285 = r61271 - r61284;
return r61285;
}



Bits error versus t
Initial program 0.0
rmApplied *-un-lft-identity0.0
Applied *-un-lft-identity0.0
Applied times-frac0.0
Simplified0.0
Simplified0.0
rmApplied log1p-expm1-u0.0
Final simplification0.0
herbie shell --seed 2019354 +o rules:numerics
(FPCore (t)
:name "Kahan p13 Example 3"
:precision binary64
(- 1 (/ 1 (+ 2 (* (- 2 (/ (/ 2 t) (+ 1 (/ 1 t)))) (- 2 (/ (/ 2 t) (+ 1 (/ 1 t)))))))))