Average Error: 5.7 → 0
Time: 2.2s
Precision: 64
\[e^{\log a + \log b}\]
↓
\[a \cdot b\]
e^{\log a + \log b}
↓
a \cdot b
double f(double a, double b) {
        double r184983 = a;
        double r184984 = log(r184983);
        double r184985 = b;
        double r184986 = log(r184985);
        double r184987 = r184984 + r184986;
        double r184988 = exp(r184987);
        return r184988;
}
↓
double f(double a, double b) {
        double r184989 = a;
        double r184990 = b;
        double r184991 = r184989 * r184990;
        return r184991;
}

Error

Bits error versus a

Bits error versus b

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original5.7
Target0
Herbie0
\[a \cdot b\]

Derivation

  1. Initial program 5.7

    \[e^{\log a + \log b}\]
  2. Using strategy rm

  3. Applied exp-sum5.5

    \[\leadsto \color{blue}{e^{\log a} \cdot e^{\log b}}\]

  4. Simplified4.8

    \[\leadsto \color{blue}{a} \cdot e^{\log b}\]

  5. Simplified0

    \[\leadsto a \cdot \color{blue}{b}\]

  6. Final simplification0

    \[\leadsto a \cdot b\]

Reproduce

herbie shell --seed 2019353 +o rules:numerics
(FPCore (a b)
  :name "Exp of sum of logs"
  :precision binary64

  :herbie-target
  (* a b)

  (exp (+ (log a) (log b))))