Average Error: 0 → 0
Time: 375.0ms
Precision: 64
\[\left(x \cdot 2\right) \cdot x\]
↓
\[\left(x \cdot 2\right) \cdot x\]
\left(x \cdot 2\right) \cdot x
↓
\left(x \cdot 2\right) \cdot x
double f(double x) {
        double r516988 = x;
        double r516989 = 2.0;
        double r516990 = r516988 * r516989;
        double r516991 = r516990 * r516988;
        return r516991;
}
↓
double f(double x) {
        double r516992 = x;
        double r516993 = 2.0;
        double r516994 = r516992 * r516993;
        double r516995 = r516994 * r516992;
        return r516995;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0
Target0
Herbie0
\[\left(2 \cdot x\right) \cdot x\]

Derivation

  1. Initial program 0

    \[\left(x \cdot 2\right) \cdot x\]

  2. Final simplification0

    \[\leadsto \left(x \cdot 2\right) \cdot x\]

Reproduce

herbie shell --seed 2019353 
(FPCore (x)
  :name "Numeric.Log:$cexpm1 from log-domain-0.10.2.1, A"
  :precision binary64

  :herbie-target
  (* (* 2 x) x)

  (* (* x 2) x))