Average Error: 63.0 → 0.0
Time: 5.5s
Precision: 64
\[n \gt 6.8 \cdot 10^{15}\]
\[\left(\left(n + 1\right) \cdot \log \left(n + 1\right) - n \cdot \log n\right) - 1\]
\[1 - \left(\left(1 + \left(\frac{0.1666666666666666851703837437526090070605}{{n}^{2}} + 1 \cdot \log \left(\frac{1}{n}\right)\right)\right) - \frac{0.5}{n}\right)\]
\left(\left(n + 1\right) \cdot \log \left(n + 1\right) - n \cdot \log n\right) - 1
1 - \left(\left(1 + \left(\frac{0.1666666666666666851703837437526090070605}{{n}^{2}} + 1 \cdot \log \left(\frac{1}{n}\right)\right)\right) - \frac{0.5}{n}\right)
double f(double n) {
        double r62878 = n;
        double r62879 = 1.0;
        double r62880 = r62878 + r62879;
        double r62881 = log(r62880);
        double r62882 = r62880 * r62881;
        double r62883 = log(r62878);
        double r62884 = r62878 * r62883;
        double r62885 = r62882 - r62884;
        double r62886 = r62885 - r62879;
        return r62886;
}

double f(double n) {
        double r62887 = 1.0;
        double r62888 = 0.16666666666666669;
        double r62889 = n;
        double r62890 = 2.0;
        double r62891 = pow(r62889, r62890);
        double r62892 = r62888 / r62891;
        double r62893 = 1.0;
        double r62894 = r62893 / r62889;
        double r62895 = log(r62894);
        double r62896 = r62887 * r62895;
        double r62897 = r62892 + r62896;
        double r62898 = r62887 + r62897;
        double r62899 = 0.5;
        double r62900 = r62899 / r62889;
        double r62901 = r62898 - r62900;
        double r62902 = r62887 - r62901;
        return r62902;
}

Error

Bits error versus n

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original63.0
Target0.0
Herbie0.0
\[\log \left(n + 1\right) - \left(\frac{1}{2 \cdot n} - \left(\frac{1}{3 \cdot \left(n \cdot n\right)} - \frac{4}{{n}^{3}}\right)\right)\]

Derivation

  1. Initial program 63.0

    \[\left(\left(n + 1\right) \cdot \log \left(n + 1\right) - n \cdot \log n\right) - 1\]
  2. Taylor expanded around inf 0.0

    \[\leadsto \color{blue}{\left(\left(0.5 \cdot \frac{1}{n} + 1\right) - \left(1 \cdot \log \left(\frac{1}{n}\right) + 0.1666666666666666851703837437526090070605 \cdot \frac{1}{{n}^{2}}\right)\right)} - 1\]
  3. Simplified0.0

    \[\leadsto \color{blue}{\left(\left(1 - \left(1 \cdot \log \left(\frac{1}{n}\right) + 0.1666666666666666851703837437526090070605 \cdot \frac{1}{{n}^{2}}\right)\right) + \frac{0.5}{n}\right)} - 1\]
  4. Using strategy rm
  5. Applied associate-+l-0.0

    \[\leadsto \color{blue}{\left(1 - \left(\left(1 \cdot \log \left(\frac{1}{n}\right) + 0.1666666666666666851703837437526090070605 \cdot \frac{1}{{n}^{2}}\right) - \frac{0.5}{n}\right)\right)} - 1\]
  6. Applied associate--l-0.0

    \[\leadsto \color{blue}{1 - \left(\left(\left(1 \cdot \log \left(\frac{1}{n}\right) + 0.1666666666666666851703837437526090070605 \cdot \frac{1}{{n}^{2}}\right) - \frac{0.5}{n}\right) + 1\right)}\]
  7. Simplified0.0

    \[\leadsto 1 - \color{blue}{\left(\left(1 + \left(\frac{0.1666666666666666851703837437526090070605}{{n}^{2}} + 1 \cdot \log \left(\frac{1}{n}\right)\right)\right) - \frac{0.5}{n}\right)}\]
  8. Final simplification0.0

    \[\leadsto 1 - \left(\left(1 + \left(\frac{0.1666666666666666851703837437526090070605}{{n}^{2}} + 1 \cdot \log \left(\frac{1}{n}\right)\right)\right) - \frac{0.5}{n}\right)\]

Reproduce

herbie shell --seed 2019353 
(FPCore (n)
  :name "logs (example 3.8)"
  :precision binary64
  :pre (> n 6.8e+15)

  :herbie-target
  (- (log (+ n 1)) (- (/ 1 (* 2 n)) (- (/ 1 (* 3 (* n n))) (/ 4 (pow n 3)))))

  (- (- (* (+ n 1) (log (+ n 1))) (* n (log n))) 1))