Average Error: 0.0 → 0.0
Time: 727.0ms
Precision: 64
\[e^{\left(x \cdot y\right) \cdot y}\]
\[e^{\left(x \cdot y\right) \cdot y}\]
e^{\left(x \cdot y\right) \cdot y}
e^{\left(x \cdot y\right) \cdot y}
double f(double x, double y) {
        double r222279 = x;
        double r222280 = y;
        double r222281 = r222279 * r222280;
        double r222282 = r222281 * r222280;
        double r222283 = exp(r222282);
        return r222283;
}

double f(double x, double y) {
        double r222284 = x;
        double r222285 = y;
        double r222286 = r222284 * r222285;
        double r222287 = r222286 * r222285;
        double r222288 = exp(r222287);
        return r222288;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[e^{\left(x \cdot y\right) \cdot y}\]
  2. Final simplification0.0

    \[\leadsto e^{\left(x \cdot y\right) \cdot y}\]

Reproduce

herbie shell --seed 2019353 +o rules:numerics
(FPCore (x y)
  :name "Data.Random.Distribution.Normal:normalF from random-fu-0.2.6.2"
  :precision binary64
  (exp (* (* x y) y)))