Average Error: 0.0 → 0.0
Time: 392.0ms
Precision: 64
\[x \cdot \left(1 - x \cdot 0.5\right)\]
↓
\[x \cdot \left(1 - x \cdot 0.5\right)\]
x \cdot \left(1 - x \cdot 0.5\right)
↓
x \cdot \left(1 - x \cdot 0.5\right)
double f(double x) {
        double r61861 = x;
        double r61862 = 1.0;
        double r61863 = 0.5;
        double r61864 = r61861 * r61863;
        double r61865 = r61862 - r61864;
        double r61866 = r61861 * r61865;
        return r61866;
}
↓
double f(double x) {
        double r61867 = x;
        double r61868 = 1.0;
        double r61869 = 0.5;
        double r61870 = r61867 * r61869;
        double r61871 = r61868 - r61870;
        double r61872 = r61867 * r61871;
        return r61872;
}

Error

Bits error versus x

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Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[x \cdot \left(1 - x \cdot 0.5\right)\]

  2. Final simplification0.0

    \[\leadsto x \cdot \left(1 - x \cdot 0.5\right)\]

Reproduce

herbie shell --seed 2019353 +o rules:numerics
(FPCore (x)
  :name "Numeric.SpecFunctions:log1p from math-functions-0.1.5.2, B"
  :precision binary64
  (* x (- 1 (* x 0.5))))