Average Error: 0 → 0
Time: 347.0ms
Precision: 64
\[\left(x \cdot 16\right) \cdot x\]
\[\left(x \cdot 16\right) \cdot x\]
\left(x \cdot 16\right) \cdot x
\left(x \cdot 16\right) \cdot x
double f(double x) {
        double r160303 = x;
        double r160304 = 16.0;
        double r160305 = r160303 * r160304;
        double r160306 = r160305 * r160303;
        return r160306;
}

double f(double x) {
        double r160307 = x;
        double r160308 = 16.0;
        double r160309 = r160307 * r160308;
        double r160310 = r160309 * r160307;
        return r160310;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0

    \[\left(x \cdot 16\right) \cdot x\]
  2. Final simplification0

    \[\leadsto \left(x \cdot 16\right) \cdot x\]

Reproduce

herbie shell --seed 2019352 +o rules:numerics
(FPCore (x)
  :name "Graphics.Rasterific.CubicBezier:isSufficientlyFlat from Rasterific-0.6.1"
  :precision binary64
  (* (* x 16) x))