Average Error: 0 → 0
Time: 613.0ms
Precision: 64
\[x = 0.0 \lor x = 10\]
\[x\]
\[x\]
x
x
double f(double x) {
        double r138 = x;
        return r138;
}

double f(double x) {
        double r139 = x;
        return r139;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0

    \[x\]
  2. Final simplification0

    \[\leadsto x\]

Reproduce

herbie shell --seed 2019351 +o rules:numerics
(FPCore (x)
  :name "x"
  :precision binary64
  :pre (or (== x 0.0) (== x 10))
  x)