Average Error: 0.0 → 0.0
Time: 17.4s
Precision: 64
\[x \cdot e^{y \cdot y}\]
\[x \cdot {\left(e^{y}\right)}^{y}\]
x \cdot e^{y \cdot y}
x \cdot {\left(e^{y}\right)}^{y}
double f(double x, double y) {
        double r655531 = x;
        double r655532 = y;
        double r655533 = r655532 * r655532;
        double r655534 = exp(r655533);
        double r655535 = r655531 * r655534;
        return r655535;
}

double f(double x, double y) {
        double r655536 = x;
        double r655537 = y;
        double r655538 = exp(r655537);
        double r655539 = pow(r655538, r655537);
        double r655540 = r655536 * r655539;
        return r655540;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.0
Target0.0
Herbie0.0
\[x \cdot {\left(e^{y}\right)}^{y}\]

Derivation

  1. Initial program 0.0

    \[x \cdot e^{y \cdot y}\]
  2. Using strategy rm
  3. Applied add-log-exp0.0

    \[\leadsto x \cdot e^{\color{blue}{\log \left(e^{y}\right)} \cdot y}\]
  4. Applied exp-to-pow0.0

    \[\leadsto x \cdot \color{blue}{{\left(e^{y}\right)}^{y}}\]
  5. Final simplification0.0

    \[\leadsto x \cdot {\left(e^{y}\right)}^{y}\]

Reproduce

herbie shell --seed 2019350 
(FPCore (x y)
  :name "Data.Number.Erf:$dmerfcx from erf-2.0.0.0"
  :precision binary64

  :herbie-target
  (* x (pow (exp y) y))

  (* x (exp (* y y))))