Average Error: 0.0 → 0.0
Time: 7.8s
Precision: 64
\[e^{\left(x \cdot y\right) \cdot y}\]
\[e^{\left(x \cdot y\right) \cdot y}\]
e^{\left(x \cdot y\right) \cdot y}
e^{\left(x \cdot y\right) \cdot y}
double f(double x, double y) {
        double r119919 = x;
        double r119920 = y;
        double r119921 = r119919 * r119920;
        double r119922 = r119921 * r119920;
        double r119923 = exp(r119922);
        return r119923;
}

double f(double x, double y) {
        double r119924 = x;
        double r119925 = y;
        double r119926 = r119924 * r119925;
        double r119927 = r119926 * r119925;
        double r119928 = exp(r119927);
        return r119928;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[e^{\left(x \cdot y\right) \cdot y}\]
  2. Final simplification0.0

    \[\leadsto e^{\left(x \cdot y\right) \cdot y}\]

Reproduce

herbie shell --seed 2019347 +o rules:numerics
(FPCore (x y)
  :name "Data.Random.Distribution.Normal:normalF from random-fu-0.2.6.2"
  :precision binary64
  (exp (* (* x y) y)))