\left(\left(x \cdot y + \frac{z \cdot t}{16}\right) - \frac{a \cdot b}{4}\right) + c\mathsf{fma}\left(\frac{z}{16}, t, \mathsf{fma}\left(x, y, \mathsf{fma}\left(\frac{a}{4}, -b, c\right)\right)\right)double f(double x, double y, double z, double t, double a, double b, double c) {
double r119082 = x;
double r119083 = y;
double r119084 = r119082 * r119083;
double r119085 = z;
double r119086 = t;
double r119087 = r119085 * r119086;
double r119088 = 16.0;
double r119089 = r119087 / r119088;
double r119090 = r119084 + r119089;
double r119091 = a;
double r119092 = b;
double r119093 = r119091 * r119092;
double r119094 = 4.0;
double r119095 = r119093 / r119094;
double r119096 = r119090 - r119095;
double r119097 = c;
double r119098 = r119096 + r119097;
return r119098;
}
double f(double x, double y, double z, double t, double a, double b, double c) {
double r119099 = z;
double r119100 = 16.0;
double r119101 = r119099 / r119100;
double r119102 = t;
double r119103 = x;
double r119104 = y;
double r119105 = a;
double r119106 = 4.0;
double r119107 = r119105 / r119106;
double r119108 = b;
double r119109 = -r119108;
double r119110 = c;
double r119111 = fma(r119107, r119109, r119110);
double r119112 = fma(r119103, r119104, r119111);
double r119113 = fma(r119101, r119102, r119112);
return r119113;
}



Bits error versus x



Bits error versus y



Bits error versus z



Bits error versus t



Bits error versus a



Bits error versus b



Bits error versus c
Initial program 0.1
Simplified0.0
Final simplification0.0
herbie shell --seed 2019347 +o rules:numerics
(FPCore (x y z t a b c)
:name "Diagrams.Solve.Polynomial:quartForm from diagrams-solve-0.1, C"
:precision binary64
(+ (- (+ (* x y) (/ (* z t) 16)) (/ (* a b) 4)) c))