Average Error: 5.7 → 0
Time: 3.7s
Precision: 64
\[e^{\log a + \log b}\]
↓
\[b \cdot a\]
e^{\log a + \log b}
↓
b \cdot a
double f(double a, double b) {
        double r93902 = a;
        double r93903 = log(r93902);
        double r93904 = b;
        double r93905 = log(r93904);
        double r93906 = r93903 + r93905;
        double r93907 = exp(r93906);
        return r93907;
}
↓
double f(double a, double b) {
        double r93908 = b;
        double r93909 = a;
        double r93910 = r93908 * r93909;
        return r93910;
}

Error

Bits error versus a

Bits error versus b

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original5.7
Target0
Herbie0
\[a \cdot b\]

Derivation

  1. Initial program 5.7

    \[e^{\log a + \log b}\]

  2. Simplified0

    \[\leadsto \color{blue}{b \cdot a}\]

  3. Final simplification0

    \[\leadsto b \cdot a\]

Reproduce

herbie shell --seed 2019326 +o rules:numerics
(FPCore (a b)
  :name "Exp of sum of logs"
  :precision binary64

  :herbie-target
  (* a b)

  (exp (+ (log a) (log b))))