Average Error: 0.0 → 0.0
Time: 8.2s
Precision: 64
\[e^{\left(x \cdot y\right) \cdot y}\]
\[e^{\left(x \cdot y\right) \cdot y}\]
e^{\left(x \cdot y\right) \cdot y}
e^{\left(x \cdot y\right) \cdot y}
double f(double x, double y) {
        double r185785 = x;
        double r185786 = y;
        double r185787 = r185785 * r185786;
        double r185788 = r185787 * r185786;
        double r185789 = exp(r185788);
        return r185789;
}

double f(double x, double y) {
        double r185790 = x;
        double r185791 = y;
        double r185792 = r185790 * r185791;
        double r185793 = r185792 * r185791;
        double r185794 = exp(r185793);
        return r185794;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[e^{\left(x \cdot y\right) \cdot y}\]
  2. Final simplification0.0

    \[\leadsto e^{\left(x \cdot y\right) \cdot y}\]

Reproduce

herbie shell --seed 2019326 
(FPCore (x y)
  :name "Data.Random.Distribution.Normal:normalF from random-fu-0.2.6.2"
  :precision binary64
  (exp (* (* x y) y)))