Average Error: 0.3 → 0.3
Time: 24.7s
Precision: 64
\[\left(x \cdot 27\right) \cdot y\]
\[\left(x \cdot 27\right) \cdot y\]
\left(x \cdot 27\right) \cdot y
\left(x \cdot 27\right) \cdot y
double f(double x, double y) {
        double r154140 = x;
        double r154141 = 27.0;
        double r154142 = r154140 * r154141;
        double r154143 = y;
        double r154144 = r154142 * r154143;
        return r154144;
}

double f(double x, double y) {
        double r154145 = x;
        double r154146 = 27.0;
        double r154147 = r154145 * r154146;
        double r154148 = y;
        double r154149 = r154147 * r154148;
        return r154149;
}

Error

Bits error versus x

Bits error versus y

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.3

    \[\left(x \cdot 27\right) \cdot y\]
  2. Final simplification0.3

    \[\leadsto \left(x \cdot 27\right) \cdot y\]

Reproduce

herbie shell --seed 2019326 
(FPCore (x y)
  :name "Diagrams.Solve.Polynomial:cubForm  from diagrams-solve-0.1, F"
  :precision binary64
  (* (* x 27) y))