0.5 \cdot \sqrt{2 \cdot \left(\sqrt{re \cdot re + im \cdot im} - re\right)}0.5 \cdot \sqrt{\left(\mathsf{hypot}\left(re, im\right) - re\right) \cdot 2}double f(double re, double im) {
double r26280 = 0.5;
double r26281 = 2.0;
double r26282 = re;
double r26283 = r26282 * r26282;
double r26284 = im;
double r26285 = r26284 * r26284;
double r26286 = r26283 + r26285;
double r26287 = sqrt(r26286);
double r26288 = r26287 - r26282;
double r26289 = r26281 * r26288;
double r26290 = sqrt(r26289);
double r26291 = r26280 * r26290;
return r26291;
}
double f(double re, double im) {
double r26292 = 0.5;
double r26293 = re;
double r26294 = im;
double r26295 = hypot(r26293, r26294);
double r26296 = r26295 - r26293;
double r26297 = 2.0;
double r26298 = r26296 * r26297;
double r26299 = sqrt(r26298);
double r26300 = r26292 * r26299;
return r26300;
}



Bits error versus re



Bits error versus im
Results
Initial program 38.4
Simplified13.2
Final simplification13.2
herbie shell --seed 2019326 +o rules:numerics
(FPCore (re im)
:name "math.sqrt on complex, imaginary part, im greater than 0 branch"
:precision binary64
(* 0.5 (sqrt (* 2 (- (sqrt (+ (* re re) (* im im))) re)))))