Average Error: 0 → 0
Time: 569.0ms
Precision: 64
\[\left(x + x\right) - 1\]
\[\left(x + x\right) - 1\]
\left(x + x\right) - 1
\left(x + x\right) - 1
double f(double x) {
        double r104250 = x;
        double r104251 = r104250 + r104250;
        double r104252 = 1.0;
        double r104253 = r104251 - r104252;
        return r104253;
}

double f(double x) {
        double r104254 = x;
        double r104255 = r104254 + r104254;
        double r104256 = 1.0;
        double r104257 = r104255 - r104256;
        return r104257;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0

    \[\left(x + x\right) - 1\]
  2. Final simplification0

    \[\leadsto \left(x + x\right) - 1\]

Reproduce

herbie shell --seed 2019326 +o rules:numerics
(FPCore (x)
  :name "Data.Random.Distribution.Normal:doubleStdNormalZ from random-fu-0.2.6.2"
  :precision binary64
  (- (+ x x) 1))