Average Error: 0.0 → 0.0
Time: 7.1s
Precision: 64
\[x \cdot \left(1 - x \cdot 0.5\right)\]
↓
\[x \cdot \left(1 - x \cdot 0.5\right)\]
x \cdot \left(1 - x \cdot 0.5\right)
↓
x \cdot \left(1 - x \cdot 0.5\right)
double f(double x) {
        double r51281 = x;
        double r51282 = 1.0;
        double r51283 = 0.5;
        double r51284 = r51281 * r51283;
        double r51285 = r51282 - r51284;
        double r51286 = r51281 * r51285;
        return r51286;
}
↓
double f(double x) {
        double r51287 = x;
        double r51288 = 1.0;
        double r51289 = 0.5;
        double r51290 = r51287 * r51289;
        double r51291 = r51288 - r51290;
        double r51292 = r51287 * r51291;
        return r51292;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0.0

    \[x \cdot \left(1 - x \cdot 0.5\right)\]

  2. Final simplification0.0

    \[\leadsto x \cdot \left(1 - x \cdot 0.5\right)\]

Reproduce

herbie shell --seed 2019326 
(FPCore (x)
  :name "Numeric.SpecFunctions:log1p from math-functions-0.1.5.2, B"
  :precision binary64
  (* x (- 1 (* x 0.5))))