Average Error: 0.1 → 0
Time: 2.9s
Precision: 64
\[\left(x \cdot x\right) \cdot x\]
↓
\[{x}^{3}\]
\left(x \cdot x\right) \cdot x
↓
{x}^{3}
double f(double x) {
        double r155968 = x;
        double r155969 = r155968 * r155968;
        double r155970 = r155969 * r155968;
        return r155970;
}
↓
double f(double x) {
        double r155971 = x;
        double r155972 = 3.0;
        double r155973 = pow(r155971, r155972);
        return r155973;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.1
Target0
Herbie0
\[{x}^{3}\]

Derivation

  1. Initial program 0.1

    \[\left(x \cdot x\right) \cdot x\]

  2. Simplified0

    \[\leadsto \color{blue}{{x}^{3}}\]

  3. Final simplification0

    \[\leadsto {x}^{3}\]

Reproduce

herbie shell --seed 2019325 +o rules:numerics
(FPCore (x)
  :name "math.cube on real"
  :precision binary64

  :herbie-target
  (pow x 3)

  (* (* x x) x))