Average Error: 0 → 0
Time: 628.0ms
Precision: 64
\[\left(x + x\right) - 1\]
\[\left(x + x\right) - 1\]
\left(x + x\right) - 1
\left(x + x\right) - 1
double f(double x) {
        double r131189 = x;
        double r131190 = r131189 + r131189;
        double r131191 = 1.0;
        double r131192 = r131190 - r131191;
        return r131192;
}

double f(double x) {
        double r131193 = x;
        double r131194 = r131193 + r131193;
        double r131195 = 1.0;
        double r131196 = r131194 - r131195;
        return r131196;
}

Error

Bits error versus x

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation

  1. Initial program 0

    \[\left(x + x\right) - 1\]
  2. Final simplification0

    \[\leadsto \left(x + x\right) - 1\]

Reproduce

herbie shell --seed 2019325 +o rules:numerics
(FPCore (x)
  :name "Data.Random.Distribution.Normal:doubleStdNormalZ from random-fu-0.2.6.2"
  :precision binary64
  (- (+ x x) 1))