Average Error: 0.1 → 0
Time: 6.2s
Precision: 64
\[\left(d1 \cdot \left(\left(\left(\left(\left(d1 \cdot \left(d1 \cdot d1\right)\right) \cdot d1\right) \cdot d1\right) \cdot \left(d1 \cdot d1\right)\right) \cdot d1\right)\right) \cdot d1\]
↓
\[{d1}^{10}\]
\left(d1 \cdot \left(\left(\left(\left(\left(d1 \cdot \left(d1 \cdot d1\right)\right) \cdot d1\right) \cdot d1\right) \cdot \left(d1 \cdot d1\right)\right) \cdot d1\right)\right) \cdot d1
↓
{d1}^{10}
double f(double d1) {
        double r176234 = d1;
        double r176235 = r176234 * r176234;
        double r176236 = r176234 * r176235;
        double r176237 = r176236 * r176234;
        double r176238 = r176237 * r176234;
        double r176239 = r176238 * r176235;
        double r176240 = r176239 * r176234;
        double r176241 = r176234 * r176240;
        double r176242 = r176241 * r176234;
        return r176242;
}
↓
double f(double d1) {
        double r176243 = d1;
        double r176244 = 10.0;
        double r176245 = pow(r176243, r176244);
        return r176245;
}

Error

Bits error versus d1

Try it out

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original0.1
Target0
Herbie0
\[{d1}^{10}\]

Derivation

  1. Initial program 0.1

    \[\left(d1 \cdot \left(\left(\left(\left(\left(d1 \cdot \left(d1 \cdot d1\right)\right) \cdot d1\right) \cdot d1\right) \cdot \left(d1 \cdot d1\right)\right) \cdot d1\right)\right) \cdot d1\]

  2. Simplified0

    \[\leadsto \color{blue}{{d1}^{10}}\]

  3. Final simplification0

    \[\leadsto {d1}^{10}\]

Reproduce

herbie shell --seed 2019325 +o rules:numerics
(FPCore (d1)
  :name "FastMath test5"
  :precision binary64

  :herbie-target
  (pow d1 10)

  (* (* d1 (* (* (* (* (* d1 (* d1 d1)) d1) d1) (* d1 d1)) d1)) d1))